Integrand size = 21, antiderivative size = 105 \[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\frac {(d+e x)^{1+m} \sqrt {b x+c x^2} \operatorname {AppellF1}\left (1+m,-\frac {1}{2},-\frac {1}{2},2+m,\frac {d+e x}{d},\frac {c (d+e x)}{c d-b e}\right )}{e (1+m) \sqrt {-\frac {e x}{d}} \sqrt {1-\frac {c (d+e x)}{c d-b e}}} \]
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Time = 0.04 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {773, 138} \[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\frac {\sqrt {b x+c x^2} (d+e x)^{m+1} \operatorname {AppellF1}\left (m+1,-\frac {1}{2},-\frac {1}{2},m+2,\frac {d+e x}{d},\frac {c (d+e x)}{c d-b e}\right )}{e (m+1) \sqrt {-\frac {e x}{d}} \sqrt {1-\frac {c (d+e x)}{c d-b e}}} \]
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Rule 138
Rule 773
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {b x+c x^2} \text {Subst}\left (\int x^m \sqrt {1-\frac {x}{d}} \sqrt {1-\frac {c x}{c d-b e}} \, dx,x,d+e x\right )}{e \sqrt {1-\frac {d+e x}{d}} \sqrt {1-\frac {d+e x}{d-\frac {b e}{c}}}} \\ & = \frac {(d+e x)^{1+m} \sqrt {b x+c x^2} F_1\left (1+m;-\frac {1}{2},-\frac {1}{2};2+m;\frac {d+e x}{d},\frac {c (d+e x)}{c d-b e}\right )}{e (1+m) \sqrt {-\frac {e x}{d}} \sqrt {1-\frac {c (d+e x)}{c d-b e}}} \\ \end{align*}
Time = 0.94 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.72 \[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\frac {2 x \sqrt {x (b+c x)} (d+e x)^m \left (\frac {d+e x}{d}\right )^{-m} \operatorname {AppellF1}\left (\frac {3}{2},-\frac {1}{2},-m,\frac {5}{2},-\frac {c x}{b},-\frac {e x}{d}\right )}{3 \sqrt {\frac {b+c x}{b}}} \]
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\[\int \left (e x +d \right )^{m} \sqrt {c \,x^{2}+b x}d x\]
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\[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\int { \sqrt {c x^{2} + b x} {\left (e x + d\right )}^{m} \,d x } \]
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\[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\int \sqrt {x \left (b + c x\right )} \left (d + e x\right )^{m}\, dx \]
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\[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\int { \sqrt {c x^{2} + b x} {\left (e x + d\right )}^{m} \,d x } \]
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\[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\int { \sqrt {c x^{2} + b x} {\left (e x + d\right )}^{m} \,d x } \]
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Timed out. \[ \int (d+e x)^m \sqrt {b x+c x^2} \, dx=\int \sqrt {c\,x^2+b\,x}\,{\left (d+e\,x\right )}^m \,d x \]
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